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For a cell, the terminal potential diffe...

For a cell, the terminal potential difference is 2.2V when circuit is open and reduces to 1.8V when cell is connected to a resistance `R=5Omega` , the internal resistance (R) of cell is

A

`10/9Omega`

B

`9/10Omega`

C

`11/9Omega`

D

`5/9Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
T.P.D (V)=E-Ir (Remember it)
V=E-`(E/(R+r))r="ER"/"(R+r)"` from given conditions E=2.2 & when R=5 then TPD V =1.8 V therefore 1.8=`(2.2xx5)/(5+r) rArr r=10/9 Omega`
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