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The magnetic field of a given length of ...

The magnetic field of a given length of wire carrying a current of a single turn circular coil at centre is B, then its value for two turns for the same wire when same current passing through it is

A

`B/4`

B

`B/2`

C

`4B`

D

`2B`

Text Solution

Verified by Experts

The correct Answer is:
C
`B_1=B=(mu_0I)/(2R)`

`B_2=(mu_0(2I))/(2r)`
`because 2 xx 2pir=2piR " " therefore r=R//2`
`rArr B_2=4(mu_0I)/(2R)=4B`
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