Home
Class 12
PHYSICS
A stationary particle explodes into two ...

A stationary particle explodes into two particle of a masses `m_(1) and m_(2)` which move in opposite direction with velocities `v_(1) and v_(2)`. The ratio of their kinetic energies `E_(1)//E_(2)` is

A

`m_2//m_1`

B

`m_1//m_2`

C

1

D

`m_1v_2//m_2v_1`

Text Solution

Verified by Experts

The correct Answer is:
A

`m_1v_1=m_2v_2(P_1=P_2)`
`E_1/E_2=(1/2m_1v_1^2)/(1/2m_2V_2^2)=((P_1^2)/(2m_1))/((P_2^2)/(2m_2))=m_2/m_1`
Promotional Banner

Similar Questions

Explore conceptually related problems

A stationary particle explodes into two particles of masses x and y, which move in opposite directions wit h velocity v_(1)and v_(2). The ratio of their kinetic energies (E_(1):E_(2)) is

Two bodies of equal masses are moving with uniform velocities v and 2v. Find the ratio of their kinetic energies

A bomb at rest explodes into two parts of masses m_(1) and m_(2) . If the momentums of the two parts be P_(1) and P_(2) , then their kinetic energies will be in the ratio of:

A stationary body explodes into two fragments of masses m_(1) and m_(2) . If momentum of one fragment is p , the energy of explosion is

A stationary body explodes into two fragments of masses m_(1) and m_(2) . If momentum of one fragment is p , the energy of explosion is

Two masses, m_(1) and m_(2) , are moving with velocities v_(1) and v_(2) . Find their total kinetic energy in the reference frame of centre of mass.

Two particles of masses m and 2m moving in opposite directions collide elastically with velocity 2v and v , respectiely. Find their velocities after collision.

Two bodies of different masses m_(1) and m_(2) have equal momenta. Their kinetic energies E_(1) and E_(2) are in the ratio

Two bodies of different masses m_(1) and m_(2) have equal momenta. Their kinetic energies E_(1) and E_(2) are in the ratio

Two bodies of different masses m_(1) and m_(2) have equal momenta. Their kinetic energies E_(1) and E_(2) are in the ratio