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A ball rolls without slipping. The radiu...

A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass is `k`. IF radius of the ball be `R`, then the fraction of total energy associated with its rotational energy will be

A

`(K^2+R^2)/R^2`

B

`K^2/R^2`

C

`K^2/(K^2+R^2)`

D

`R^2/(K^2+R^2)`

Text Solution

Verified by Experts

The correct Answer is:
C
T.K.E.=`1/2mv^2(1+K^2//R^2)`
R.K.E.=`1/2mv^2(K^2//R^2)`
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