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A particle of mass m(1) is moving with a...

A particle of mass` m_(1)` is moving with a velocity `v_(1)` and another particle of mass `m_(2)` is moving with a velocity `v_(2)`. Both of them have the same momentum, but their different kinetic energies are `E_(1) "and" E_(2)` respectively. If `m_(1)gtm_(2)`, then

A

`E_1/E_2=m_1/m_2`

B

`E_1 gt E_2`

C

`E_1=E_2`

D

`E_1 lt E_2`

Text Solution

Verified by Experts

The correct Answer is:
D

`because E=rho^2/"2m"therefore Eprop 1/m` if `m_1 gt m_2` then ` E_1 lt E_2`
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