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The phase difference between two waves. ...

The phase difference between two waves.
`y_(1)= 10^(-6) sin{100 t + (x/50)+ 0.5}m`
`y_(2)= 10^(-6) sin{100 t + (x/50)}m`
where, x is expressed in metre and t is expressed in second , is approximately

A

2.07 radians

B

0.5 radians

C

1.5 radians

D

1.07 radians

Text Solution

Verified by Experts

The correct Answer is:
D
`y_1=10^(-6) sin { 100 t + x/50 +0.5 }`
`y_2=10^(-6) cos {100t+x/50}`
`=10^(-6) sin { pi/2 + 100t +x/50}`
Phase difference between `y_1` & `y_2 =pi/2 -0.5` =1.58-0.5 =1.08 radians
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