Using anhydrous `AlCl_(3)` as catalyst, which one of the following reactions produces ethylbenzene `(PhEt)` ?

Options

A. `CH_3-CH=CH_2+C_6H_6`
B. `H_2C=CH_2+C_6H_6`
C. `H_3C-CH_3+C_6H_6`
D. `H_3C-CH_2OH+C_6H_6`

Answer

To determine which reaction produces ethylbenzene (PhEt) using anhydrous AlCl₃ as a catalyst, we will analyze each option provided in the question.

### Step 1: Understanding the Reactions
Anhydrous AlCl₃ is a Lewis acid catalyst commonly used in Friedel-Crafts alkylation reactions, where an alkene reacts with benzene to form an alkyl-substituted benzene.

### Step 2: Evaluating Each Option
- **Option A: Propene with Benzene**
- Propene (C₃H₆) can react with benzene in the presence of AlCl₃. The reaction will produce isopropylbenzene (cumene) rather than ethylbenzene.

- **Option B: Ethene with Benzene**
- Ethene (C₂H₄) reacts with benzene in the presence of AlCl₃ to form ethylbenzene (C₆H₅C₂H₅). This is the correct reaction that produces the desired product.

- **Option C: Ethane with Benzene**
- Ethane (C₂H₆) does not react with benzene in the presence of AlCl₃. This reaction does not occur because ethane is not an alkene and cannot form a carbocation.

- **Option D: Ethyl Alcohol with Benzene**
- Ethyl alcohol (C₂H₅OH) does not react with benzene in the presence of AlCl₃ to form ethylbenzene. This reaction does not occur as well.

### Conclusion
The correct answer is **Option B: Ethene with Benzene**, which produces ethylbenzene when reacted in the presence of anhydrous AlCl₃.

### Final Answer
**Option B: Ethene with Benzene produces ethylbenzene (PhEt).**

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