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A photosensitive metallic surface has wo...

A photosensitive metallic surface has work function, `h v_(0)`. If photons of energy `2hv_(0)` fall on this surface, the electrons come out with a maximum velocity of `4 xx 10^(6) m/s`. When the photon energy is increased to `5hv_(0)`, then photon energy is increased to photoelectrons will be

A

`2 xx 10^(7) m//s `

B

`2xx10^(6) m//s`

C

`8xx10^(5) m//s `

D

`8xx10^(6) m//s `

Text Solution

Verified by Experts

The correct Answer is:
D
`2hv_(0)=hv_(0)+(1)/(2)m(4xx10^(6))^(2)`
`5hv_(0)=hv_(0)+(1)/(2) mv^(2)implies 4 xx (1)/(2)m(4 xx 10^(6))`
`=(1)/(2)mv^(2)implies v =8xx10^(6)m/s`
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