Home
Class 12
PHYSICS
A network of four capacitors of capacity...

A network of four capacitors of capacity equal to `C_(1) = C, C_(2) = 2C, C_(3) = 3C` and `C_(4) = 4C` are connected to a battery as charges on `C_(2)` and `C_(4)` is

A

`(7)/(4)`

B

`(22)/(3)`

C

`(3)/(22)`

D

`(4)/(7)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A network of four capacitors of capacity equal to C_(1) = C, C_(2) = 2C, C_(3) = 3C and C_(4) = 4C are connected to a battery as shown in the figure. The ratio of the charges on C_(2) an C_(4) is

A network of four capacitors of capacity equal to C_(1) = C, C_(2) = 2C, C_(3) = 3C and C_(4) = 4C are connected to a battery as shown in the figure. The ratio o fthe charges on C_(2) an C_(4) is

Find the cahrge on capacitor C_(3) Given , that C_(1) = C_(2) = C and C_(3) = C_(4) = 3C

Find the charge on capacitor C_(3) Given, then C_(1) = C_(2) and C_(3) = C_(4) = 3 C .

A capacitor of capacity C_(1) = 1 muF is charged to a potential of 100 V. The charging battery is then removed and it is connected to another capacitor of capacity C_(2) = 2 muF . One plate of C_(2) is earthed as shown in figure. The charges on C_(1) and C_(2) in steady state will be

Deduce an expression for equivalent capacitance C when three capacitors C_(1), C_(2) and C_(3) are connected in parallel.

Three capacitors C_1 = 3muF, C_2 = 6muF and C_3 = 10muF are connected to a 50 V battery as shown in the figure below: Calculate : The charge on C_1

In the network of capacitors given ahead. Find the effective capacitance between point P and Q If C_(1)=C_(2)=C_(3)=C_(4)=4 muF Value is not given C_(1) and C_(2)

Four capacitors C_(1)=8 muF , C_(2)=2 muf, C_(3)=6 muF , and C_(4)=6, muF are arranged as shown in. Find the charge on all the capacitors in the circuit. .

In the given network of capacitors as shown in, given that C_(1) = C_(2)C_(3)=400pF , and C_(4)=C_(5)=C_(6)=200pF , The effective capacitance of the circuit between X and Y is.