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Products of the following reaction, CH...

Products of the following reaction,
`CH_(3)-Cequiv"CC"H_(2)CH_(3)underset((ii)"Hydrolysis")overset((i) O_(3))to`? are:

A

`CH_(3)COOH+ CH_(3)COCH_(3)`

B

`CH_(3)COOH+HOOC.CH_(2)CH_(3)`

C

`CH_(3)CHO+CH_(3)CH_(2)CHO`

D

`CH_(3)COOH+CO_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to follow the steps of the reaction involving the compound CH3-C≡C-CH2-CH3 with ozone (O3) followed by hydrolysis. ### Step-by-Step Solution: 1. **Identify the Reactant:** The reactant is CH3-C≡C-CH2-CH3, which is 1-pentyne (an alkyne). 2. **Ozonolysis Reaction:** When 1-pentyne reacts with ozone (O3), it undergoes ozonolysis. This reaction cleaves the triple bond and forms an unstable ozonide intermediate. The structure can be represented as: \[ CH3-C(=O)-C(=O)-CH2-CH3 \] Here, the triple bond between the carbon atoms is broken, and two carbonyl groups are formed. 3. **Hydrolysis of Ozonide:** The unstable ozonide then undergoes hydrolysis (reaction with water). This process converts the ozonide into carboxylic acids. The hydrolysis will yield: \[ CH3-C(=O)-OH \quad \text{(Ethanoic acid)} \] and \[ CH3-CH2-C(=O)-OH \quad \text{(Propanoic acid)} \] 4. **Final Products:** The final products of the reaction after ozonolysis and hydrolysis are: - Ethanoic acid (acetic acid) \( CH3COOH \) - Propanoic acid \( CH3CH2COOH \) ### Conclusion: The products of the reaction are Ethanoic acid and Propanoic acid.
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