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Assuming the sun to have a spherical out...

Assuming the sun to have a spherical outer surface of radius `r` radiating like a black body at temperature `t^(@)C`. The power received by a unit surface (normal to the incident rays) at a distance `R` from the centre of the sun is
where `sigma` is the Stefan's constant.

A

`r(2) sigma (t+273)^(4)//R^(2)`

B

`4 pi r^(2) sigmat^(4)//R^(2)`

C

`r^(2) sigma (t+273)^(4)//4piR^(2)`

D

`16pi^(2)r^(2) sigma t^(4)//R^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the power received by a unit surface (normal to the incident rays) at a distance \( R \) from the center of the Sun, given that the Sun behaves like a black body radiating at a temperature \( t \) (in degrees Celsius). ### Step-by-Step Solution: 1. **Convert Temperature to Kelvin**: The temperature \( t \) in degrees Celsius needs to be converted to Kelvin. The conversion formula is: \[ T = t + 273 \] 2. **Calculate the Total Power Radiated by the Sun**: The total power \( P \) radiated by the Sun can be calculated using the Stefan-Boltzmann law: \[ P = \sigma A T^4 \] where \( A \) is the surface area of the Sun. The surface area of a sphere is given by: \[ A = 4\pi r^2 \] Thus, substituting for \( A \): \[ P = \sigma (4\pi r^2) (T^4) = 4\pi r^2 \sigma (t + 273)^4 \] 3. **Calculate the Power per Unit Area at Distance \( R \)**: The power received per unit area at a distance \( R \) from the center of the Sun can be found by dividing the total power by the surface area of a sphere of radius \( R \): \[ \text{Power per unit area} = \frac{P}{4\pi R^2} \] Substituting the expression for \( P \): \[ \text{Power per unit area} = \frac{4\pi r^2 \sigma (t + 273)^4}{4\pi R^2} \] 4. **Simplify the Expression**: The \( 4\pi \) terms cancel out: \[ \text{Power per unit area} = \frac{r^2 \sigma (t + 273)^4}{R^2} \] 5. **Final Expression**: Thus, the power received by a unit surface at a distance \( R \) from the center of the Sun is: \[ \text{Power per unit area} = \sigma \frac{r^2}{R^2} (t + 273)^4 \] ### Final Answer: The power received by a unit surface at a distance \( R \) from the center of the Sun is: \[ \text{Power per unit area} = \sigma \frac{r^2}{R^2} (t + 273)^4 \]

To solve the problem, we need to find the power received by a unit surface (normal to the incident rays) at a distance \( R \) from the center of the Sun, given that the Sun behaves like a black body radiating at a temperature \( t \) (in degrees Celsius). ### Step-by-Step Solution: 1. **Convert Temperature to Kelvin**: The temperature \( t \) in degrees Celsius needs to be converted to Kelvin. The conversion formula is: \[ T = t + 273 ...
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