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The particle executing simple harmonic m...

The particle executing simple harmonic motion has a kinetic energy `K_(0) cos^(2) omega t`. The maximum values of the potential energy and the energy are respectively

A

`K_(0) and K_(0)`

B

`0 and 2K_(0)`

C

`(K_(0))/(2) and K_(0)`

D

`K_(0) and 2K_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
`:. K.E. =K_(0) cos^(2) omegat` ltbtgt `:.` Maximum P.E.= Maximum K.E. = Total energy =`K_(0)`
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