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Two radioactive substances A and B have ...

Two radioactive substances A and B have decay constants `5lambda` and `lambda` respectively. At t=0 , they have the same number of nuclei. The ratio of number of nuclei of A of those of B will be `(1//e)^2` after a time interval

A

`(1)/(2 lambda)`

B

`(1)/(4 lambda )`

C

`4 lambda `

D

`2 lambda `

Text Solution

Verified by Experts

The correct Answer is:
A
`(N_(A))/(N_(B))=(N_(0)e^(-lambda_(A)t))/(N_(0)e^(-lambda_(B)t))=(e^(-5lambdat))/(e^(-lambdat))`
`implies (1)/(e^(4lambdat))=(1)/(e^(2))impliest=(1)/(2 lambda)`
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