The total energy of an electron in the g...

The total energy of an electron in the ground state of hydrogen atom is `-13.6` eV. The kinetic energy of an electron in the first excited state is

1.7 ev

3.4 eV

6.8 eV

13.6 eV

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The correct Answer is:

Total energy in first excited state `=-(13.4)/(4)=-3.4 eV`
K.E. in first excited state =- total energy in that state =- (-3.4)=3.4eV

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