Home
Class 12
PHYSICS
The distance travelled by a particle sta...

The distance travelled by a particle starting from rest and moving with an acceleration `(4)/(3)ms^(-2)`, in the thrid-second is

A

`(10)/(3)m`

B

`(19)/(3)m`

C

6m

D

4m

Text Solution

Verified by Experts

The correct Answer is:
A

Distance covered in `n^(th)` second.
`S_(n)=u+(1)/(2)a(2n-1),`
`=0+(1)/(2)xx(4)/(3)(2xx3-1)`
`=(1)/(2)xx(4)/(3)xx5=(10)/(3)m`
Promotional Banner

Similar Questions

Explore conceptually related problems

The distance travelled by a particle starting from rest and moving with an acceleration (4)/(3) ms^-2 , in the third second is.

The distance travelled by a particle starting from rest and moving with an acceleration (4)/(3) ms^-2 , in the third second is.

The distance travelled by a particle starting from rest and moving with an acceleration 3 ms^-2 , in the 5th second is.

A body starts from rest and then moves with uniform acceleration. Then.

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is:

A particle starts moving with acceleration 2 m//s^(2) . Distance travelled by it in 5^(th) half second is

A body starting from rest has an acceleration of 4ms^(-2) . Calculate distance travelled by it in 5th second.

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be