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Two nuclei have their mass numbers in th...

Two nuclei have their mass numbers in the ratio of 1:3. The ratio of their nuclear densities would be

A

`(3)^(1//3):1`

B

`1:1`

C

`1:3`

D

`3:1`

Text Solution

Verified by Experts

The correct Answer is:
B
`R=R_(0).A^(1//3)`
So nuclear density `=(A.m)/(v)`
m = mass of each nucleon, A = mass number
`=(3m)/(4piR_(0)^(3))=" independent of A."`
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