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the wave described bt Y= 0.25 sin (10 ...

the wave described bt
`Y= 0.25 sin (10 pi xx - 2 xxt)`
where , x and y are in metre and t in second, is a wave travelling along the

A

`+ ve` x direction with frequency 1 Hz and wavelength `lambda = 0.2 m`

B

`–ve` x direction with amplitude 0.25 m and wavelength `lambda = 0.2 m`

C

`– ve` x direction with frequency 1 Hz

D

`+ ve` x direction with frequency π Hz and wavelength `lambda= 0.2m`

Text Solution

Verified by Experts

The correct Answer is:
A
Given `y=0.25 sin (10pix-2pit)`
Comparing with equation of wave
`y=A sin (kx-omegat)`
`A=0.25, k=10pi, omega=2pi`
`(2pi)/(lambda)=10pi" "2pif=2pi`
`f=1Hz`
`lambda=(1)/(5)=0.2m`
When sign of coefficient of t and x are opposite it means `(dx)/(dt)=V gt 0` i.e., wave is propagating in the direction of growing x.
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