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IF the concentration of OH^(-) ions is t...

IF the concentration of `OH^(-)` ions is the reaction. `Fe(OH)_(3)hArrFe^(3+)(aq)+3OH^(-)(aq)` is decreased by `1//4` times, then equilibrium concentration of `Fe^(3+)` will increase by

A

64 times

B

4 times

C

8 times

D

16 times

Text Solution

Verified by Experts

The correct Answer is:
A
`Fe(OH)_(3)(s)hArr Fe^(3+)(aq.)+3OH^(-)(aq.)`
`K=([Fe^(3+)][OH^(-)]^(3))/([Fe(OH)_(3)])`
`K=[Fe^(3+)][OH^(-)]^(3)`
`K=Fe^(3+)][OH^(-)]^(3)`
(as activity of solid is taken unity)
Concentration of `OH^(-)` ion in the reaction is decreased by 1/4 times then equilibrium concentration of `Fe^(3+)` will be increased by 64 times in order to keep the value of K constant.
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