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What is the volume of one molecules of w...

What is the volume of one molecules of water (density of `H_(2) O = 1 g cm^(-3)`)

A

`3.0xx10^(-23)cm^(3)`

B

`5.5xx10^(-23)cm^(3)`

C

`9.0xx10^(-23)cm^(3)`

D

`6.023xx10^(-23)cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Weight of `6.023xx10^(23)` molecules of water = 18 g As volume occupied by `6.023xx10^(23)` molecules of water (dneisty `= "1 g cm"^(-3)`) will be
`=(18g)/(1gcm^(-3))`
`="18 cm"^(3)"or mL"`
So volume occupied by one molecule of water
`=(18)/(6.023xx10^(23))=2.988xx10^(-23)`
`=3.0xx10^(-23)cm^(3)`
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