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Let vecF be a force acting on a particle...

Let `vecF` be a force acting on a particle having positon vector `vecr. Let vectau` be the torque of this force about the origin then

A

`vecr. vectau=0 and vecF. vectau ne0`

B

`vecr. vectau ne 0 and vecF. vectau =0`

C

`vecr. vectau gt 0 and vecF. vectau lt 0`

D

`vecr. vectau=0 and vecF. vectau = 0`

Text Solution

Verified by Experts

The correct Answer is:
D
`vec(tau)=vecrxx vecF`
`vec(tau)` is perpendicular to `vecr and vecF`
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