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The IUPAC name of the compound having th...

The `IUPAC` name of the compound having the formula `CH-=C-CH=CH_(2)` is

A

1-butene-3-yne

B

3-buten-1-yne

C

1-butyn-3-ene

D

but-1-yn-3-ene

Text Solution

AI Generated Solution

The correct Answer is:
To determine the IUPAC name of the compound with the formula CH≡C-CH=CH₂, we will follow these steps: ### Step 1: Identify the longest carbon chain The given compound has a total of 4 carbon atoms. The longest chain is: - C1: CH (with a triple bond) - C2: C (with a double bond) - C3: CH - C4: CH₂ ### Step 2: Number the carbon chain We need to number the carbon chain in such a way that the double and triple bonds get the lowest possible numbers. Starting from the end closest to the triple bond: 1. C1: CH (triple bond) 2. C2: C (double bond) 3. C3: CH 4. C4: CH₂ So, the numbering is as follows: - C1: Triple bond - C2: Double bond - C3: CH - C4: CH₂ ### Step 3: Identify the types of bonds - The triple bond is located between C1 and C2. - The double bond is located between C2 and C3. ### Step 4: Assign the IUPAC name According to IUPAC nomenclature: - The root name for 4 carbon atoms is "but". - Since there is a double bond at C2, we use "ene". - Since there is a triple bond at C1, we use "yne". The correct order of naming is to place the double bond before the triple bond in the name. Thus: - The name will be 1-butyne (for the triple bond) and 2-ene (for the double bond). Combining these, we get the IUPAC name: **1-butyne-2-ene**. ### Final Answer: The IUPAC name of the compound CH≡C-CH=CH₂ is **1-butyne-2-ene**. ---

To determine the IUPAC name of the compound with the formula CH≡C-CH=CH₂, we will follow these steps: ### Step 1: Identify the longest carbon chain The given compound has a total of 4 carbon atoms. The longest chain is: - C1: CH (with a triple bond) - C2: C (with a double bond) - C3: CH - C4: CH₂ ...
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