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Identify (Z) in the following series. ...

Identify (Z) in the following series.
`Ethanol overset(PBr_(3))to (X) overset(Alc.//KOH)to (Y) overset((i)H_(2)SO_(4)//("Room temp")) underset((ii)(H_(2)O,Heat))to(Z)`

A

`CH_(3)CH_(2)-OH`

B

`CH_(2)=CH_(2)`

C

`CH_(3)CH_(2)-o-CH_(2)CH_(3)`

D

`CH_(3)CH_(2)-O-SO_(3)H`

Text Solution

AI Generated Solution

The correct Answer is:
To identify compound (Z) in the given reaction series, we will analyze each step of the reactions systematically. ### Step 1: Reaction of Ethanol with PBr3 - **Starting Compound**: Ethanol (C₂H₅OH) - **Reaction**: Ethanol reacts with phosphorus tribromide (PBr₃). - **Product (X)**: The hydroxyl group (OH) in ethanol is replaced by a bromine atom (Br), resulting in bromoethane (C₂H₅Br). **Chemical Equation**: \[ \text{C}_2\text{H}_5\text{OH} + \text{PBr}_3 \rightarrow \text{C}_2\text{H}_5\text{Br} + \text{HBr} + \text{H}_3\text{PO}_3 \] ### Step 2: Reaction of Bromoethane with Alcoholic KOH - **Starting Compound**: Bromoethane (C₂H₅Br) - **Reaction**: Bromoethane undergoes elimination when treated with alcoholic KOH. - **Product (Y)**: The reaction removes HBr, leading to the formation of ethene (C₂H₄). **Chemical Equation**: \[ \text{C}_2\text{H}_5\text{Br} + \text{KOH (alc)} \rightarrow \text{C}_2\text{H}_4 + \text{HBr} + \text{KBr} \] ### Step 3: Reaction of Ethene with Sulfuric Acid - **Starting Compound**: Ethene (C₂H₄) - **Reaction**: Ethene reacts with sulfuric acid (H₂SO₄) at room temperature, followed by hydrolysis (addition of water with heat). - **Product (Z)**: The addition of H₂SO₄ introduces a proton (H⁺) to one carbon and the bisulfate ion (HSO₄⁻) to the other carbon. Upon hydrolysis, the bisulfate is replaced by a hydroxyl group (OH), resulting in ethanol (C₂H₅OH). **Chemical Equation**: 1. Addition of H₂SO₄: \[ \text{C}_2\text{H}_4 + \text{H}_2\text{SO}_4 \rightarrow \text{C}_2\text{H}_5\text{OSO}_3\text{H} \] 2. Hydrolysis: \[ \text{C}_2\text{H}_5\text{OSO}_3\text{H} + \text{H}_2\text{O} \rightarrow \text{C}_2\text{H}_5\text{OH} + \text{H}_2\text{SO}_4 \] ### Conclusion The final product (Z) after the complete series of reactions is ethanol (C₂H₅OH). ### Answer: **(Z) is Ethanol (C₂H₅OH)** ---

To identify compound (Z) in the given reaction series, we will analyze each step of the reactions systematically. ### Step 1: Reaction of Ethanol with PBr3 - **Starting Compound**: Ethanol (C₂H₅OH) - **Reaction**: Ethanol reacts with phosphorus tribromide (PBr₃). - **Product (X)**: The hydroxyl group (OH) in ethanol is replaced by a bromine atom (Br), resulting in bromoethane (C₂H₅Br). **Chemical Equation**: ...
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