Trichloroacetaldehyde, `C Cl_(3)CHO` reacts with chlorobenzene in presence of sulphuric acid and produces.

Options

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Explanation

To solve the problem of what product is formed when trichloroacetaldehyde (CCl3CHO) reacts with chlorobenzene in the presence of sulfuric acid, we can follow these steps:

### Step 1: Identify the Reactants
We have two reactants:
1. Trichloroacetaldehyde (CCl3CHO)
2. Chlorobenzene (C6H5Cl)

### Step 2: Understand the Reaction Conditions
The reaction occurs in the presence of sulfuric acid (H2SO4), which acts as a catalyst. This suggests that we may be looking at a condensation reaction where water is eliminated.

### Step 3: Draw the Structures
- **Trichloroacetaldehyde (CCl3CHO)** has a carbonyl group (C=O) and a formyl group (–CHO).
- **Chlorobenzene (C6H5Cl)** is a benzene ring with a chlorine substituent.

### Step 4: Reaction Mechanism
The reaction involves the formation of a new bond between the carbon of the trichloroacetaldehyde and the chlorobenzene. The aldehyde group will react with the chlorobenzene, leading to the elimination of a water molecule (H2O).

### Step 5: Form the Product
The product formed from this reaction is **Dichlorodiphenyltrichloroethane (DDT)**. The structure can be represented as follows:
- The central carbon is bonded to the trichloro group (CCl3).
- On either side of this carbon, there are two chlorobenzene rings (C6H5).

### Step 6: Final Structure
The final structure can be depicted as:
- A central carbon atom bonded to a trichloro group (CCl3).
- Two chlorobenzene rings (C6H5) attached to the central carbon.

### Conclusion
The product formed from the reaction of trichloroacetaldehyde with chlorobenzene in the presence of sulfuric acid is **Dichlorodiphenyltrichloroethane (DDT)**.