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The electric field on an electromagnetic...

The electric field on an electromagnetic wave in free space is given by
`E=10 cos (10^7t+kx) hatj V//m`,
Where t and x are in seconds and metres respectively. It can be inferred that
(1) the wavelength `lambda` is `188.4m`.
(2) the wave number k is `0.33rad//m`
(3) the wave amplitude is `10V//m`
(4) the wave is propagating along +x direction.
which one of the following pairs of statement is correct?

A

(a) and (b)

B

(b) and (c )

C

(a) and (c )

D

(c ) and (d)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we will analyze the electric field of the electromagnetic wave and derive the necessary parameters step by step. ### Step 1: Identify the given electric field equation The electric field of the electromagnetic wave is given by: \[ E = 10 \cos(10^7 t + kx) \hat{j} \, \text{V/m} \] ### Step 2: Determine the amplitude of the wave The amplitude \( E_0 \) of the wave is the coefficient in front of the cosine function. From the equation: \[ E_0 = 10 \, \text{V/m} \] ### Step 3: Identify the angular frequency \( \omega \) The angular frequency \( \omega \) is the coefficient of \( t \) in the argument of the cosine function. From the equation: \[ \omega = 10^7 \, \text{rad/s} \] ### Step 4: Calculate the wavelength \( \lambda \) The relationship between the speed of light \( c \), angular frequency \( \omega \), and wavelength \( \lambda \) is given by: \[ c = \omega \lambda \] Rearranging gives: \[ \lambda = \frac{c}{\omega} \] Using \( c \approx 3 \times 10^8 \, \text{m/s} \): \[ \lambda = \frac{3 \times 10^8}{10^7} = 30 \, \text{m} \] ### Step 5: Calculate the wave number \( k \) The wave number \( k \) is related to the wavelength by: \[ k = \frac{2\pi}{\lambda} \] Substituting the value of \( \lambda \): \[ k = \frac{2\pi}{30} \approx 0.209 \, \text{rad/m} \] ### Step 6: Determine the direction of propagation The wave is represented in the form \( E = E_0 \cos(\omega t + kx) \hat{j} \). The positive sign before \( kx \) indicates that the wave is propagating in the negative x-direction. However, since the electric field is in the \( \hat{j} \) direction, it implies that the wave is propagating in the positive x-direction. ### Summary of Results 1. Amplitude \( E_0 = 10 \, \text{V/m} \) 2. Angular frequency \( \omega = 10^7 \, \text{rad/s} \) 3. Wavelength \( \lambda = 30 \, \text{m} \) 4. Wave number \( k = 0.209 \, \text{rad/m} \) 5. Direction of propagation: +x direction ### Conclusion Based on the calculations, the correct statements are: - The wave amplitude is \( 10 \, \text{V/m} \) (True). - The wave is propagating along the +x direction (True). - The wavelength \( \lambda \) is not \( 188.4 \, \text{m} \) but \( 30 \, \text{m} \) (False). - The wave number \( k \) is not \( 0.33 \, \text{rad/m} \) but \( 0.209 \, \text{rad/m} \) (False).
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