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The decay constant of a radioactive isot...

The decay constant of a radioactive isotope is `lambda`. If `A_1` and `A_2` are its activites at time `t_1` and `t_2` respectively, then the number of nuclei which have decayed the time `(t_1-t_2)`

A

`A_(1)-A_(2)`

B

`(A_(1)-A_(2))//lambda`

C

`lambda(A_(1)-A_(2))`

D

`(A_(1)t_(1)-A_(2)t_(2)`

Text Solution

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The correct Answer is:
B
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