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A 0.66 kg ball is moving wih a speed of ...

A `0.66 kg` ball is moving wih a speed of `100 m//s`. The associated wavelength will be.

A

`6.6xx10^(-34)m`

B

`1.0xx10^(-35)m`

C

`1.0xx10^(-32)m`

D

`6.6xx10^(-32)m`

Text Solution

AI Generated Solution

The correct Answer is:
To find the associated wavelength of a moving ball using De Broglie's equation, we can follow these steps: ### Step 1: Understand De Broglie's Equation De Broglie's equation relates the wavelength (λ) of a particle to its momentum. The equation is given by: \[ \lambda = \frac{h}{mv} \] where: - \( \lambda \) is the wavelength, - \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)), - \( m \) is the mass of the particle in kilograms, - \( v \) is the velocity of the particle in meters per second. ### Step 2: Identify the Given Values From the question, we have: - Mass of the ball, \( m = 0.66 \, \text{kg} \) - Velocity of the ball, \( v = 100 \, \text{m/s} \) ### Step 3: Substitute the Values into the Equation Now, we can substitute the values of \( h \), \( m \), and \( v \) into the De Broglie's equation: \[ \lambda = \frac{6.626 \times 10^{-34}}{0.66 \times 100} \] ### Step 4: Calculate the Denominator Calculate the product of mass and velocity: \[ mv = 0.66 \times 100 = 66 \, \text{kg m/s} \] ### Step 5: Calculate the Wavelength Now substitute the value of \( mv \) back into the equation: \[ \lambda = \frac{6.626 \times 10^{-34}}{66} \] ### Step 6: Perform the Division Now perform the division: \[ \lambda = 1.0039 \times 10^{-35} \, \text{m} \] ### Step 7: Final Result Thus, the associated wavelength of the ball is approximately: \[ \lambda \approx 1.0 \times 10^{-35} \, \text{m} \] ### Summary The associated wavelength of the 0.66 kg ball moving at a speed of 100 m/s is \( \lambda \approx 1.0 \times 10^{-35} \, \text{m} \). ---
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Knowledge Check

  • A body of mass 10 mg is moving with a velocity of 100 ms^(-1) . The wavelength of the de Broglie wave associated with it would be

    A
    `6.626xx10^(-7)`m
    B
    `6.626xx10^(-34)`m
    C
    `6.626xx10^(-4)`m
    D
    `6.626xx10^(-35)`m
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