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A particle move a distance x in time t a...

A particle move a distance `x` in time `t` according to equation `x = (t + 5)^-1`. The acceleration of particle is proportional to.

A

(Velocity )`""^(3//2)`

B

(Distance)`""^(2)`

C

(Distance )`""^(-2)`

D

(Velocity )`""^(2//3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`x=(1)/(t+5)implies v=(dx)/(dt)=-(1)/((t+5)^(2))`
`"Accerleration ,a" = (dx)/(dt)=(2)/((t+5)^(3))`
`implies a prop"(velocity )"^(3//2)`
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