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A conducting circular loop is placed in ...

A conducting circular loop is placed in a uniform magnetic field, B = 0.025 T with its plne perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of `1mm s^(-1)` . The induced emf when the radius is 2 cm, is

A

`2 pi mu V`

B

`pi mu V`

C

`(pi)/(2)mu V`

D

`2mu V`

Text Solution

Verified by Experts

The correct Answer is:
B
`phi =(B)(pir^(2))implies e=(dphi)/(dt)=(B)(2pir)((dr)/(dt))`
`=(0.025)(2pi )(2xx10^(-2)(10^(-3))=pimuV`
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