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When an alpha-particle of mass m moving ...

When an `alpha`-particle of mass `m` moving with velocity `v` bombards on heavy nucleus of charge `Ze`, its distance of closest approach from the nucleus depends on `m` as

A

`(1)/(ze)`

B

`V^(2)`

C

`(1)/(m)`

D

`(1)/(v^(4))`

Text Solution

Verified by Experts

The correct Answer is:
C
`(1)/(2)mv^(2)=((ze)(2e))/(4piin_(0)d_(min))"then"d_(min) prop(1)/(m)`
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