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A source S(1) is producing 10^(15) photo...

A source `S_(1)` is producing `10^(15)` photons per second of wavelength `5000Ã…`. Another source `S_(2)` is producing 1.02xx10^(15) wavelength 5100 A Then, `("Power of" S_(2))//("Power of"S_(1))` is equal to

A

1

B

1.02

C

10.4

D

0.98

Text Solution

Verified by Experts

The correct Answer is:
A
`("power of "S_(2))/("power of"S_(1))=(n_(2)((hc)/(lamda_(2))))/(n_(1)((hc)/(lamda_(1))))=(n_(2)lamda_(1))/(n_(1)lamda_(2))=1`
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