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A common emitter amplifier has a voltage...

A common emitter amplifier has a voltage gain of `50`, an input impedence of `100 Omega` and an output impedence of `200 Omega`. The power gain of the of the amplifier is

A

500

B

1000

C

1250

D

50

Text Solution

AI Generated Solution

The correct Answer is:
To find the power gain of the common emitter amplifier, we can follow these steps: ### Step 1: Understand the Definitions The power gain (P_gain) of an amplifier can be defined as the ratio of output power (P_out) to input power (P_in). It can also be expressed in terms of voltage gain (A_v) and the ratio of output current (I_out) to input current (I_in). ### Step 2: Write the Formula for Power Gain The power gain can be expressed as: \[ P_{\text{gain}} = \frac{P_{\text{out}}}{P_{\text{in}}} = \frac{V_{\text{out}} \cdot I_{\text{out}}}{V_{\text{in}} \cdot I_{\text{in}}} \] ### Step 3: Express Output Voltage and Input Voltage Given that the voltage gain (A_v) is defined as: \[ A_v = \frac{V_{\text{out}}}{V_{\text{in}}} = 50 \] ### Step 4: Relate Output Current and Input Current The relationship between output current (I_out) and input current (I_in) can be derived from the input and output impedances: - Input impedance (R_in) = 100 Ω - Output impedance (R_out) = 200 Ω Using the current relationship: \[ \frac{I_{\text{out}}}{I_{\text{in}}} = \frac{R_{\text{in}}}{R_{\text{out}}} \] We can express: \[ I_{\text{out}} = \frac{R_{\text{in}}}{R_{\text{out}}} \cdot I_{\text{in}} = \frac{100}{200} \cdot I_{\text{in}} = 0.5 \cdot I_{\text{in}} \] ### Step 5: Substitute Values into Power Gain Formula Now substituting the values into the power gain formula: \[ P_{\text{gain}} = \frac{V_{\text{out}} \cdot I_{\text{out}}}{V_{\text{in}} \cdot I_{\text{in}}} \] Substituting \( V_{\text{out}} = 50 \cdot V_{\text{in}} \) and \( I_{\text{out}} = 0.5 \cdot I_{\text{in}} \): \[ P_{\text{gain}} = \frac{(50 \cdot V_{\text{in}}) \cdot (0.5 \cdot I_{\text{in}})}{V_{\text{in}} \cdot I_{\text{in}}} \] ### Step 6: Simplify the Expression Cancelling \( V_{\text{in}} \) and \( I_{\text{in}} \) from the numerator and denominator: \[ P_{\text{gain}} = 50 \cdot 0.5 = 25 \] ### Step 7: Calculate the Final Power Gain Thus, the power gain of the amplifier is: \[ P_{\text{gain}} = 25 \] ### Final Answer The power gain of the common emitter amplifier is **25**. ---

To find the power gain of the common emitter amplifier, we can follow these steps: ### Step 1: Understand the Definitions The power gain (P_gain) of an amplifier can be defined as the ratio of output power (P_out) to input power (P_in). It can also be expressed in terms of voltage gain (A_v) and the ratio of output current (I_out) to input current (I_in). ### Step 2: Write the Formula for Power Gain The power gain can be expressed as: \[ P_{\text{gain}} = \frac{P_{\text{out}}}{P_{\text{in}}} = \frac{V_{\text{out}} \cdot I_{\text{out}}}{V_{\text{in}} \cdot I_{\text{in}}} \] ...
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