The reaction of toluene with `CI_(2)` in presence of `FeCI_(3)` gives `X` and reaction in presence of light gives `Y` Thus `X` and `Y` are .

Options

A. X = Benzal chloride,
Y = o-chlorotoluene
B. X = m– chlorotoluene,
Y = p- chlorotoluene
C. X = o-and p- chlorotoluene
Y = Trichloromethyl benzene
D. X = Benzyl chloride,
Y = m- chlorotoluene

Answer

To solve the question, we need to analyze the reactions of toluene with chlorine under different conditions.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have toluene (C7H8), which consists of a benzene ring with a methyl group (-CH3) attached to it.

2. **Reaction of Toluene with Chlorine in Presence of FeCl3**:
- When toluene reacts with chlorine (Cl2) in the presence of iron(III) chloride (FeCl3), it undergoes an electrophilic aromatic substitution reaction.
- The chlorine replaces one of the hydrogen atoms on the aromatic ring, leading to the formation of chlorinated toluene products.
- The possible products are ortho-chlorotoluene and para-chlorotoluene.
- Therefore, we can denote these products as:
- **X = ortho-chlorotoluene and para-chlorotoluene**.

3. **Reaction of Toluene with Chlorine in Presence of Light**:
- When toluene reacts with chlorine in the presence of light, it undergoes a free radical substitution reaction.
- The methyl group (-CH3) can be substituted by chlorine atoms through a series of radical steps.
- This results in the formation of trichloromethylbenzene (C6H3Cl3), where three chlorine atoms replace the hydrogen atoms of the methyl group.
- Thus, we can denote this product as:
- **Y = trichloromethylbenzene**.

4. **Final Products**:
- Therefore, the final answers for the products are:
- **X = ortho-chlorotoluene and para-chlorotoluene**.
- **Y = trichloromethylbenzene**.

### Summary of Products:
- **X**: ortho-chlorotoluene and para-chlorotoluene
- **Y**: trichloromethylbenzene