Aniline in a set of the following reactions yielded a coloured product 'Y'.
The structure of 'Y' would be:

Options

A.
B.
C.
D.

Answer

To solve the question regarding the colored product 'Y' obtained from aniline through a series of reactions, we can break down the process step by step.

### Step 1: Formation of Diazonium Salt
Aniline (C6H5NH2) is treated with sodium nitrite (NaNO2) and hydrochloric acid (HCl) at low temperatures. This reaction converts the amino group (-NH2) into a diazonium group (-N2+), forming benzenediazonium chloride.

**Reaction:**
\[ \text{C}_6\text{H}_5\text{NH}_2 + \text{NaNO}_2 + \text{HCl} \rightarrow \text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{NaCl} + 2\text{H}_2\text{O} \]

### Step 2: Coupling Reaction
The diazonium salt (C6H5N2+Cl-) is then reacted with N,N-dimethylaniline (C6H5N(CH3)2). This is a coupling reaction where the diazonium group reacts with the aromatic ring of N,N-dimethylaniline to form an azo compound.

**Reaction:**
\[ \text{C}_6\text{H}_5\text{N}_2^+ + \text{C}_6\text{H}_5\text{N(CH}_3)_2 \rightarrow \text{C}_6\text{H}_5\text{N}_2\text{C}_6\text{H}_4\text{N(CH}_3)_2 + \text{H}^+ \]

### Step 3: Structure of the Product 'Y'
The product formed from the coupling reaction is an azo dye, which typically has a vivid color. The structure of the azo dye formed in this reaction can be represented as follows:

- The azo group (-N=N-) connects the two aromatic rings (one from the diazonium compound and the other from N,N-dimethylaniline).

### Final Structure of 'Y':
The colored compound 'Y' is an azo dye with the following structure:
\[ \text{C}_6\text{H}_5\text{N}_2\text{C}_6\text{H}_4\text{N(CH}_3)_2 \]

### Conclusion:
The colored product 'Y' formed from the reactions involving aniline is an azo dye, which is typically red in color.

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