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An ideal gas goes from state A to state ...

An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram -
If `Q_(1),Q_(2),Q_(3)` indicate the heat absorbed by the gas along the three process and `DeltaU_(1),DeltaU_(2),DeltaU_(3)`, indicate the change in internal energy along the three processes respectively, then -

A

`Q_(3)gt Q_(2)gtQ_(1) and DeltaU_(1)=DeltaU_(2)=DeltaU_(3)`

B

`Q_(1)=Q_(2)=Q_(3) and DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`

C

`Q_(3) gt Q_(2) gt Q_(1) and DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`

D

`Q_(1)gt Q_(2) gt Q_(3) and DeltaU_(1)=DeltaU_(2)=DeltaU_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`dU_(1)=dU_(2)=dU_(3)`
`Q_(1) gt Q_(2) gt Q_(3)`
because `DeltaQ=DeltaW+dU`
Change in internal energy independent from path and work depends on path and `DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`
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