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The half-life of a radioactive nucleus i...

The half-life of a radioactive nucleus is `50` days. The time interval `(t_2 -t_1)` between the time `t_2` when `(2)/(3)` of it has decayed and the time `t_1` when `(1)/(3)` of it had decayed is

A

50 days

B

60 days

C

15 days

D

30 days

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To solve the problem, we need to find the time interval \( (t_2 - t_1) \) between the times when \( \frac{2}{3} \) of the radioactive nuclei have decayed and when \( \frac{1}{3} \) of them have decayed. The half-life of the radioactive nucleus is given as 50 days. ### Step-by-step Solution: 1. **Understanding Decay**: - When \( \frac{1}{3} \) of the nuclei have decayed, \( \frac{2}{3} \) of the original nuclei remain undecayed. - When \( \frac{2}{3} \) of the nuclei have decayed, \( \frac{1}{3} \) of the original nuclei remain undecayed. 2. **Setting Up the Equations**: - Let \( N_0 \) be the initial number of undecayed nuclei. - At time \( t_1 \) (when \( \frac{1}{3} \) has decayed): \[ N(t_1) = N_0 \left( \frac{2}{3} \right) = N_0 \left( \frac{1}{2} \right)^{\frac{t_1}{T}} \] Here, \( T \) is the half-life (50 days). - At time \( t_2 \) (when \( \frac{2}{3} \) has decayed): \[ N(t_2) = N_0 \left( \frac{1}{3} \right) = N_0 \left( \frac{1}{2} \right)^{\frac{t_2}{T}} \] 3. **Forming the Equations**: - From the equations above, we can write: \[ \frac{2}{3} = \left( \frac{1}{2} \right)^{\frac{t_1}{T}} \quad \text{(1)} \] \[ \frac{1}{3} = \left( \frac{1}{2} \right)^{\frac{t_2}{T}} \quad \text{(2)} \] 4. **Dividing the Equations**: - Dividing equation (1) by equation (2): \[ \frac{\frac{2}{3}}{\frac{1}{3}} = \frac{\left( \frac{1}{2} \right)^{\frac{t_1}{T}}}{\left( \frac{1}{2} \right)^{\frac{t_2}{T}}} \] - This simplifies to: \[ 2 = \left( \frac{1}{2} \right)^{\frac{t_1 - t_2}{T}} \] 5. **Equating Exponents**: - Since the bases are the same, we can equate the exponents: \[ 1 = \frac{t_2 - t_1}{T} \] - Rearranging gives: \[ t_2 - t_1 = T \] 6. **Substituting the Half-Life**: - We know \( T = 50 \) days, so: \[ t_2 - t_1 = 50 \text{ days} \] ### Final Answer: The time interval \( (t_2 - t_1) \) is **50 days**.

To solve the problem, we need to find the time interval \( (t_2 - t_1) \) between the times when \( \frac{2}{3} \) of the radioactive nuclei have decayed and when \( \frac{1}{3} \) of them have decayed. The half-life of the radioactive nucleus is given as 50 days. ### Step-by-step Solution: 1. **Understanding Decay**: - When \( \frac{1}{3} \) of the nuclei have decayed, \( \frac{2}{3} \) of the original nuclei remain undecayed. - When \( \frac{2}{3} \) of the nuclei have decayed, \( \frac{1}{3} \) of the original nuclei remain undecayed. ...
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