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A rod of length 10 cm lies along the pri...

A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in such a way that its end closer to the pole is `20 cm` away from the mirror. The length of the image is

A

15 cm

B

2.5 cm

C

5 cm

D

10 cm

Text Solution

Verified by Experts

The correct Answer is:
C

Image position of end A
`(1)/(v_(A))+(1)/(-20)=(1)/(-10)`
`v_(A)=-20cm`
Image position of the end B
`(1)/(v_(B))+(1)/(-30)=(1)/(-10)`
`(1)/(v_(B))=-(1)/(15)`
`v_(B)=-15cm`
Length of the image is
`L_(A'B')=|v_(A)|-|v_(B)|=20-15=5cm`
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