Home
Class 12
PHYSICS
The ratio of amplitude of magnetic field...

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to

A

reciprocal of speed of light in vacuum

B

the ratio of magnetic permeability to the electric susceptibility of vacuum

C

unity

D

the speed of light in vacuum

Text Solution

Verified by Experts

The correct Answer is:
A
`c=(E_(0))/(B_(0))`
`(B_(0))/(E_(0))=(1)/(c)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacumm is equal to

The electric and magnetic field of an electromagnetic wave is

The ratio of amplitude B_(0) and E_(0) of the magnetic electric fields associated with an electromagnetic wave is

How does a charge q oscillating at certain frequency produce electromagnetic waves ? Sketch a schematic diagram depicting electric and magnetic fields for an electromagnetic wave propagating along the Z-direction.

The amplitude of electric field in an electromagnetic wave is 60 Vm^(-1) . Then the amplitude of magnetic field is

Write the relation for the speed of electromagnetic wave in terms of the amplitudes of electric and magnetic fields.

The amplitudes of electric and magnetic fields are related to each other as

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B_0=510 nT . What is the amplitude of the electric field part of the wave?

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B_0=510 nT . What is the amplitude of the electric field part of the wave?