Which of the following compounds will give a yellow precipitate with iodine alkali?

Options

A. Methyl acetate
B. Acetamide
C. 2-Hydroxypropane
D. Acetophenone

Explanation

To determine which compounds will give a yellow precipitate with iodine alkali, we need to identify compounds that can undergo the Iodoform test. The Iodoform test is positive for compounds that contain the methyl ketone group (CH3C=O) or a secondary alcohol that can be oxidized to a methyl ketone.

### Step-by-Step Solution:

1. **Identify the Compounds**: We have four compounds to analyze:
- Methyl acetate
- Acetamide
- 2-Hydroxypropane
- Acetophenone

2. **Analyze Methyl Acetate**:
- Structure: CH3C(=O)OCH3
- This compound is an ester and does not contain the methyl ketone group (CH3C=O).
- **Conclusion**: Methyl acetate will NOT give a yellow precipitate.

3. **Analyze Acetamide**:
- Structure: CH3C(=O)NH2
- This compound is an amide and does not contain the methyl ketone group.
- **Conclusion**: Acetamide will NOT give a yellow precipitate.

4. **Analyze 2-Hydroxypropane**:
- Structure: CH3CH(OH)CH3
- This compound is a secondary alcohol. Upon oxidation, it can form a methyl ketone (acetone).
- **Conclusion**: 2-Hydroxypropane WILL give a yellow precipitate.

5. **Analyze Acetophenone**:
- Structure: C6H5C(=O)CH3
- This compound is a methyl ketone, which satisfies the condition for the Iodoform test.
- **Conclusion**: Acetophenone WILL give a yellow precipitate.

6. **Final Answer**:
- The compounds that will give a yellow precipitate with iodine alkali are **2-Hydroxypropane** and **Acetophenone**.