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In the following sequence of reaction ...

In the following sequence of reaction
`CH_(3)-Br overset(KCN)rarrA overset(H_(3)O+)rarrBunderset(Ether)overset(LiAIH_(4))rarrC`
the end product is .

A

Acetaldehyde

B

Ethyl alcohol

C

Acetone

D

Methane

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze each reaction in the sequence provided: 1. **Starting Reaction**: - We start with `CH3Br` (Bromomethane). - When `CH3Br` reacts with `KCN` (Potassium cyanide), a nucleophilic substitution reaction occurs. The cyanide ion (CN⁻) replaces the bromine atom (Br). - **Product A**: The product formed is `CH3CN` (Acetonitrile). 2. **Second Reaction**: - Now, `CH3CN` reacts with `H3O+` (Hydronium ion). This reaction involves hydrolysis of the nitrile group. - The nitrile undergoes hydrolysis to form a carboxylic acid. - **Product B**: The product formed is `CH3COOH` (Acetic acid). 3. **Third Reaction**: - Next, `CH3COOH` reacts with `LiAlH4` (Lithium aluminium hydride) in the presence of ether. Lithium aluminium hydride is a strong reducing agent. - The carboxylic acid is reduced to an alcohol. - **Product C**: The product formed is `CH3CH2OH` (Ethyl alcohol). Thus, the final product C is **Ethyl Alcohol**. ### Final Answer: The end product is Ethyl Alcohol (C = CH3CH2OH). ---
To solve the problem step by step, we will analyze each reaction in the sequence provided: 1. **Starting Reaction**: - We start with `CH3Br` (Bromomethane). - When `CH3Br` reacts with `KCN` (Potassium cyanide), a nucleophilic substitution reaction occurs. The cyanide ion (CN⁻) replaces the bromine atom (Br). - **Product A**: The product formed is `CH3CN` (Acetonitrile). 2. **Second Reaction**: ...
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