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The molar specific heats of an ideal gas...

The molar specific heats of an ideal gas at constant pressure and volume are denoted by `C_(p)` and `C_(v)` respectively. If `gamma = (C_(p))/(C_(v))` and R is the universal gas constant, then `C_(v)` is equal to

A

`(1+gamma)/(1-gamma)`

B

`(R)/((gamma-1))`

C

`((gamma-1))/(R)`

D

`gammaR`

Text Solution

Verified by Experts

The correct Answer is:
B
`C_(p)-C_(v)=R`
`rArr(C_(p))/(C_(v))-(C_(v))/(C_(v))=(R)/(C_(v))`
`gamma-1=(R)/(C_(v))`
`therefore C_(v)=(R)/(gamma-1)`
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