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The wavelength lambda(e) of an electron ...

The wavelength `lambda_(e)` of an electron and `(lambda_(p)` of a photon of same energy E are related by

A

`lambda_(p)proplambda_(e)^(2)`

B

`lambda_(p)proplambda_(e)`

C

`lambda_(p)propsqrt(lambda_(e))`

D

`lambda_(p)prop(1)/(sqrt(lambda_(e)))`

Text Solution

Verified by Experts

The correct Answer is:
A
de- Broglie wavelength for an electron
`lambda_(e)=(h)/(sqrt(2mE))or lambda_(e)prop (1)/(sqrt(E))`
`or lambda_(e)^(2)prop (1)/(E) " " `...(1)
Wavelength of photon `rArr lambda_(p)=(hc)/(E)`
`or lambda_(p) prop (1)/(E) " " ` ...(2)
From equation (1) and (2)
`lambda_(e)^(2) prop lambda_(p)`
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