Assuming complete ionisation, same moles of which of the following compounds will require the least amount of acidified `KMnO_(4)` for complete oxidation?

Options

A. `FeC_(2)O_(4)`
B. `Fe(NO_(2))_(2)`
C. `FeSO_(4)`
D. `FeSO_(3)`

Answer

C

Explanation

` underset(v.f=5)(KMnO_(4))+underset(v.f.=3)(FeC_(2)O_(4))toMn^(+2)+Fe^(+3)+CO_(2)`
`underset(v.f=5)(KMnO_(4))+underset(v.f.=5)(Fe(NO_(2))_(2))toMn^(+2)+Fe^(+3)+NO_(3)^(-)`
Similarity of moles of `Fe(NO_(2))_(2)` is x
`n_(KMnO_(4))=(5x)/(5)=x`
`underset(v.f=5)(KMnO_(4))+underset(v.f=1)(FeSO_(4))toMn^(+2)+Fe^(+3)`
and also the moles of `FeSO_(4)` is x
`n_(KMnO_(4))=(x)/(5)`
`underset(v.f=5)(KMnO_(4))+underset(v.f=3)(FeSO_(3))toMn^(+2)+SO_(4)^(2-)+Fe^(+3)`
and also the moles of `FeSO_4` is x
`n_(KMnO_(4))=(3x)/(5)`