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What is the pH of the resulting solution...

What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed ?

A

7

B

1.04

C

12.65

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
Let volume of each solution is V.
Acid=Eq. of HCl=0.01`xxV`, Base=Equivalent of NaOH=0.1`xxV`
Net equivalent=0.1V-0.01V
`=V[0.1-0.01]`
=0.09V
`thereforeNxx2V=0.9V` (basic)
`[OH]^(Theta)N=(0.09)/(2)=4.5xx10^(-2)`
`pOH=2-log4.5`
`=2-0.65`
=1.35 ltbr `thereforepH=14-1.35=12.65`
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