The Young's modulus of steel of steel is twics that of brass. Cross -section, one of steel and another of brass are suspended from the same roff. It we want the lower ends of the weight added to the steel and brass whires must be in the ratio of

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `4:1`

Answer

C

Explanation

`Y_("stell")=2Y_("brass")`
`L_(s)=L_(b)`
`A_(s)=A_(b)`
`DeltaL_(s)=DeltaL_(b)`
`Y=("Stress")/("Strain")=((F)/(A))/((DeltaL)/(L))=(WL)/(ADeltaL)`
`W=(YA DeltaL)/(L) prop Y`
`(W_(s))/(W_(b))=(Y_(s))/(Y_(b))=2:1`