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On a frictionless surface, a block of ma...

On a frictionless surface, a block of mass M moving at speed v collides elastically with another block of same mass M which is intially at rest. After collision the first block moves at an angle `theta` to its initial direction and has a speed `v/3`. The second block's speed after the collision is

A

`(sqrt(3))/(@)v`

B

`(2sqrt(2))/(3)v`

C

`(3)/(4)v`

D

`(3)/(sqrt(2))v`

Text Solution

Verified by Experts

The correct Answer is:
B

Using conservation of K.E.
`(1)/(2)Mv^(2)+0=(1)/(2)M((v)/(3))^92)+(1)/(2)Mv_(2)^(2)`
`v^(2)=(v^(2))/(9)=v_(2)^(2)`
`v_(2)^(2)=(8v^(2))/(9)`
`v_(2)=(2sqrt(2)v)/(3)`
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