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The half-life of a radioactive substance...

The half-life of a radioactive substance is 30 min. The time (in minutes) taken between `40%` decay and `85%` decay of the same radioactive substance is

A

15

B

30

C

45

D

60

Text Solution

Verified by Experts

The correct Answer is:
D

`D.P_(1)=40%impliesA.P_(1)60%impliest_(1)`
`D.P_(2)=35%T_(1//2)log_(10)((1)/(A.P_(1)))`
`t_(2)=3.32T_(1//2)log_(10)((1)/(A.P_(2)))`
`t_(2)-t_(1)=3.32T_(1//2)[log_(10)((A.P_(1))/(A.P_(2)))]`
`=3.32xx30[log_(10)((60//100)/(15//100))]`
`=3.32xx30log_(10)4`
`=3.32xx30xx2log_(10)2`
`=59.95`
=60
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