Home
Class 12
CHEMISTRY
The percentage of pyridine (C(5)H(5)N) t...

The percentage of pyridine `(C_(5)H_(5)N)` that forms pyridinium ion `(C_(5)H_(5)N^(+)H)` in a 0.10 M aqueous pyridine solution (`K_(b)` for `C_(5)H_(5)N=1.7xx10^(-9)`) is

A

6.0E-5

B

0.00013

C

0.0077

D

0.016

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha=sqrt((K_(b))/(C))` ltBrgt `=sqrt((1.7xx10^(-9))/(0.1))`
`=sqrt(1.7xx10^(-8))`
`=1.3xx10^(-4)`
`=1.3xx10^(-2)%`
Promotional Banner

Similar Questions

Explore conceptually related problems

Aniline, C_(6)H_(5)NH_(2) react with water according to the equation C_(6)H_(5)NH_(2)(aq)+H_(2)O(I)hArrC_(6)H_(5)NH_(3)^(+)(aq)+OH^(-)(aq) In a 0.180 M aqueous aniline solution the [OH^(-)]=8.80xx10^(-6)M The value of the base ionization constant K_(b) for C_(6)H_(5)NH_(2)(aq) and the percent ionization of C_(6)H_(5)NH_(2) in this solution are,

What is the pH of a 0.10 M C_(6)H_(5)O^(-) solution? The K_(a) of C_(6)H_(5)OH is 1.0xx10^(-10)

A 0.25 M solution of pyridinium chloride C_(5)H_(5)NH^(+)Cl^(-) was found to have a pH of 2.75 What is K_(b) for pyridine, C_(5)H_(5)N ?

A 0.25M solution of pyridinium chloride (C_(5)H_(5)overset(o+)NHCl^(Theta)) has pH of 2.89 . Calculate pK_(b) for pyridine (C_(5)H_(5)N) .

Equilibrium constant for the following reaction is 1xx10^(-9) : C_(5)H_(5)N(aq.)+H_(2)O(l)hArrC_(5)H_(5)NH^(+)(aq.)+OH^(-)(aq.) Determine the moles of pyridinium chloride (C_(5)H_(5)N.HCL) is added to 500ml of 0.4M of pyridine (C_(5)H_(5)N) obtain a buffer solution of pH=5 :

and C_(2)H_(5)-O-N=O are examples of

The number of structural isomers for C_(5)H_(10) are:

Iodobenzene (C_(6)H_(5)l) is prepared from aniline (C_(6)H_(5)NH_(2)) in a two step process as shown below C_(6)H_(5)NH_(2) + HNO_(2) + HCl rarr C_(6)H_(5)N_(2) .^(+)Cl^(-) + 2H_(2)O " "C_(6)H_(5)N_(2) .^(+)Cl^(-) + KI rarr C_(6)H_(5)I + N_(2) + KCl In an actual preparation 9.30 g of aniline was coverted to 16.32 g of iodobenzene. The percentage yield of iodobenzene is :

Calculate the pH of 1.0 xx 10^(-3) M sodium phenolate NaOC_(6)H_(5) K_(a) for C_(6)H_(5)OH is 1 xx 10^(-10)