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Which of the of the following fluoro -co...

Which of the of the following fluoro -compouds is most likely to beahve as a Lewis base?

A

`BF_(3)`

B

`PF_(3)`

C

`CF_(4)`

D

`SiF_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given fluoro-compounds behaves as a Lewis base, we need to analyze the electron configuration and the presence of lone pairs in each compound. A Lewis base is defined as an electron-rich species that can donate an electron pair. ### Step-by-Step Solution: 1. **Identify the Compounds**: The compounds given are BF3, PF3, CF4, and SiF4. 2. **Understand Lewis Base**: A Lewis base must have a lone pair of electrons available for donation. 3. **Analyze BF3**: - **Valence Electrons**: Boron (B) has 3 valence electrons, and each Fluorine (F) has 7 valence electrons. - **Total Valence Electrons**: 3 (B) + 3 × 7 (F) = 24 electrons. - **Structure**: Boron forms three bonds with three fluorine atoms and has no lone pairs left. - **Conclusion**: BF3 does not act as a Lewis base. 4. **Analyze PF3**: - **Valence Electrons**: Phosphorus (P) has 5 valence electrons, and each Fluorine (F) has 7 valence electrons. - **Total Valence Electrons**: 5 (P) + 3 × 7 (F) = 26 electrons. - **Structure**: Phosphorus forms three bonds with fluorine and has 2 lone pairs remaining. - **Conclusion**: PF3 can act as a Lewis base due to the presence of lone pairs. 5. **Analyze CF4**: - **Valence Electrons**: Carbon (C) has 4 valence electrons, and each Fluorine (F) has 7 valence electrons. - **Total Valence Electrons**: 4 (C) + 4 × 7 (F) = 32 electrons. - **Structure**: Carbon forms four bonds with four fluorine atoms and has no lone pairs left. - **Conclusion**: CF4 does not act as a Lewis base. 6. **Analyze SiF4**: - **Valence Electrons**: Silicon (Si) has 4 valence electrons, and each Fluorine (F) has 7 valence electrons. - **Total Valence Electrons**: 4 (Si) + 4 × 7 (F) = 32 electrons. - **Structure**: Silicon forms four bonds with four fluorine atoms and has no lone pairs left. - **Conclusion**: SiF4 does not act as a Lewis base. 7. **Final Conclusion**: The only compound that behaves as a Lewis base is PF3, as it has lone pairs available for donation. ### Answer: **PF3** is the compound that is most likely to behave as a Lewis base.

To determine which of the given fluoro-compounds behaves as a Lewis base, we need to analyze the electron configuration and the presence of lone pairs in each compound. A Lewis base is defined as an electron-rich species that can donate an electron pair. ### Step-by-Step Solution: 1. **Identify the Compounds**: The compounds given are BF3, PF3, CF4, and SiF4. 2. **Understand Lewis Base**: A Lewis base must have a lone pair of electrons available for donation. ...
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