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The compound that will react most readil...

The compound that will react most readily with gaseous bromine has the formula

A

`C_(3)H_(6)`

B

`C_(2)H_(2)`

C

`C_(4)H_(10)`

D

`C_(2)H_(4)`

Text Solution

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The correct Answer is:
To determine which compound reacts most readily with gaseous bromine, we need to analyze the given options based on their structure and the type of bonds they contain. The options provided are: 1. C3H6 2. C2H2 3. C4H10 4. C2H4 ### Step-by-Step Solution: **Step 1: Identify the Types of Compounds** - C3H6 is propene (an alkene). - C2H2 is acetylene (an alkyne). - C4H10 is butane (an alkane). - C2H4 is ethene (an alkene). **Step 2: Understand Electrophilic Addition Reaction** Electrophilic addition reactions occur when compounds with high electron density react with electrophiles. Alkenes (compounds with double bonds) are more reactive in these reactions compared to alkanes (single bonds) and alkynes (triple bonds). **Step 3: Analyze Reactivity of Each Compound** - **C3H6 (Propene)**: This is an unsymmetrical alkene. It has a double bond, which provides a site for electrophilic attack. - **C2H2 (Acetylene)**: This is an alkyne with a triple bond. Although it can react with bromine, it is less reactive than alkenes in electrophilic addition. - **C4H10 (Butane)**: This is an alkane with only single bonds, making it the least reactive towards bromine. - **C2H4 (Ethene)**: This is a symmetrical alkene and also has a double bond, allowing for electrophilic addition. **Step 4: Compare the Alkenes** Among the alkenes (C3H6 and C2H4), propene (C3H6) is unsymmetrical, which generally makes it more reactive in electrophilic addition reactions compared to symmetrical alkenes like ethene (C2H4). **Conclusion:** The compound that will react most readily with gaseous bromine is **C3H6 (Propene)**.

To determine which compound reacts most readily with gaseous bromine, we need to analyze the given options based on their structure and the type of bonds they contain. The options provided are: 1. C3H6 2. C2H2 3. C4H10 4. C2H4 ### Step-by-Step Solution: ...
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