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A spring of force constant k is cut into...

A spring of force constant k is cut into lenghts of ratio 1:2:3 is k'. If they are connecated in parallel and force constant is k'' then k':k''is

A

`1:6`

B

`1:9`

C

`1:11`

D

`1:14`

Text Solution

Verified by Experts

The correct Answer is:
C

Spring constant `prop (1)/("length")`
`k prop (1)/(l)`
i.e, `k_(1)=6k`
`k_(2)=3k`
`k_(3)=2K`
In series
`(1)/(k')=(1)/(6k)+(1)/(3k)+(1)/(2k)`
`(1)/(k')=(6)/(6k)`
k'=k
k"=6k+3k+2k
k"=11k
`(k')/(k")=(1)/(11) ` i.e. k':k"=1:11
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